In an electron microscope, we use energetic particles because of______________?
A. Penetrating power is high
B. Kinetic energy is large
C. Wavelength is very short
D. All the above reasons

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A. Penetrating power is high
B. Kinetic energy is large
C. Wavelength is very short
D. All the above reasons
A. Wave property
B. Particle property
C. Energy particle
D. Electromagnetic wave property
A. Particle property
B. Wave property
C. Light property
D. Quantum property
A. v = 3 ×× 106 ms-1
B. v = 2 ×× 10 ms-1
C. v = 2 ×× 6 ms-1
D. v = 2 ×× 106 ms-1
A. 5.53 x 10-36kg
B. 0 kg.
C. 2.46 x 10-36kg
D. 1.84 x 10-44kg
A. Zero
B. Double
C. Half
D. 1
A. The maximum kinetic energy of the photoelectrons increases
B. The minimum kinetic energy of the photoelectrons decreases
C. The minimum kinetic energy of the photoelectrons increases
D. The average kinetic energy of the photoelectrons decreases
A. Becomes double
B. Remains same
C. Becomes half
D. First increases then decrease because of the curvilinear graph
A. Increases because wavelength decreases
B. Decreases because speed decreases
C. Remains same
D. Increases then decrease